Walt Disney prospectus Essay Example | Topics and Well Written Essays - 1000 words

Walt Disney prospectus - Essay Example It is important to note that unsecured debt notes issued to public involves significant amount of risk for the company as well as the investors. This is because from the perspective of the customer, the interest rate may be too expensive. As a result, if the company is unable to generate sufficient profits, the company’s cost of borrowings will eventually exceed the revenues which will further increase financial risk of the company. The company has however kept these issues in mind and taken appropriate measures to minimize the impact of such undesirable consequences that might be followed after issue of unsecured debt by making the offer more attractive to customers. The company believed that if the offer would be attractive then more people will be encouraged to participate which will further ensure successful marketability of these securities. One of the initiatives taken by the company to increase the marketability of the securities was to reduce the entry load for joining the scheme. The minimum number of units required to subscribe by the people in order to join the scheme was reduced to five. In order to make the offer more attractive, the company allowed public to subscribe five units of shares at two hundred and fifty dollars for non-shareholders and they would be allowed to invest as low as fifty dollar per month. The company even kept the option of cash investment open for the investors. The company also lowered enrolment fee at an affordable price of $5-$10 per investor (Reuters, 2012). 2. List the dollar amount of debt Disney proposed to sell to the public. Indicate whether this amount has increased or decreased from 2008 to 2010. Discuss some potential causes of this increase or decrease. Answer: Walt Disney has sold bonds worth three billion dollars at the end of 2012. In the year 2011, the company has sold 5, 10, and 30 years bonds with historically low coupon rates consequently increasing the price of bond in markets (Financial News, 201 1). This was one of the measures taken by the company to control coupon rates which were historically high during 2010. The issue of unsecured notes has experienced a steady decline from the period 2008 to 2010. The declining trend touched the lowest value in 2010 which continued till 2011. From the above discussion it can be said that a number of financial factors influenced the decision regarding decrease in amount of debt sold by the company to public. One of the reasons for such decline was the company’s decision to offer debt was the offer to lower coupon rates creating an opening for the company to cash in and make profits. The company took advantage of lower interest rates to maximize profits and expected the issue of bond to yield at least $1.5 billion which the company plans to utilize for corporate purpose. 3. Determine the percentage of the sales price Disney nets after discounts and commissions. Indicate whether this amount as decreased or increased from 2008 to 2 010. Discuss some potential causes of this increase or decrease. Answer: Walt Disney has been able to net sufficient percentage of sales price after discounts and commissions on the issue of sale of debt instruments. In the year 2008, the company reported 57% percentage of sales price whereas the percentage declined to 46% for the year 2010. The decrease in the amount of debt issued by the company and the

International relation class Essay Example | Topics and Well Written Essays - 250 words - 1

International relation class - Essay Example declare war on America minutes after they pulled out of the talks but several circumstances hindered the passing of the maessage in time leading to what became the worst attacks on Japanese soil. The concept of the film is based on the conflict that led to a great loss of life due to lack of amicable ways to resolve the conflict that existed. The theme of international relationships is prevalent as poor relations between the two nations had disastrous consequences. International relations can be defined as the relationship between countries and the roles government and non-governmental agencies play in fostering these relationships (Carlsnaes, 2013). The film highlights the importance of positive international relations to the growth of a country and the importance of proper conflict management techniques within international circles. Countries and nations need to co-exist together and respect the sovereignty of each other. There is also a need to have conflict resolution forums to ensure conflict between nations are resolve in a way that will have minimum negative effect to the countries relations (Baylis,

Child Abuse in Ireland: Policies and Legislation

Child Abuse in Ireland: Policies and Legislation In recent years, child abuse has been acknowledged as a growing problem in Ireland (DoHC, 1999). Since the publication of the Child Abuse Guidelines in 1987 (DoHC, 1987), a number of reforms have been introduced which aim to promote the protection and welfare of children. Healthcare professionals play an important role in child protection and care (Crisp and Lister, 2004). Community-based nurses, such as public health nurses, are frequently among the first to detect signs of child abuse and it is therefore important for them to have a full understanding both of their professional responsibilities in relation to this key role, and of relevant legislation, strategies and guidelines. In recent years, the Child Care Act 1991, Children Act 2001, Children First guidelines and the National Children’s Strategy have served to place children at the forefront of health and social care in Ireland. Legislation There is a wide variety of legislation relating to children. The United Nations Convention on the Rights of the Child (UN, 1989) was the first legally binding document to address all aspects of human rights (i.e. civil, cultural, economic, political and social) in relation to children, and recognise that individuals under the age of 18 years require additional care and protection. The Convention states that the basic human rights of all children are: the right to survival; to develop to the fullest; and to participate fully in family, cultural and social life and is underpinned by 4 principles: non-discrimination; devotion to the best interests of the child; the right to life; and respect for the views of the child. In Ireland, the main legislation relating to child care is the Child Care Act 1991, which contains provisions relating to the care, protection and welfare of children in Ireland (Government of Ireland, 1991). This Act contains 7 parts which covers the promotion of child welfare, including taking children into care, homeless children and adoption services; rules on the protection of children in emergencies and care orders; jurisdiction and procedures to ensure the welfare of the child is paramount in court proceedings; rules relating to children in care; and rules on the supervision of pre-school services and children’s residential centres. Under this Act, the Health Service Executive (HSE) has a duty to ensure the welfare of those children who are not receiving adequate care and protection through identification of children at risk, and the provision of child care and family support services. Other key legislative provisions include the Domestic Violence Act 1996; Protection for Persons Reporting Child Abuse Act 1998; The Data Protection Act 1988; the Education Act 1998; the Non-Fatal Offences Against the Person Act 1997; and the Freedom of Information Act 1997. Strategies and guidelines The Children First: National Guidelines for the Protection and Welfare of Children guidelines (DoHC, 1999a) aim to offer assistance in identifying, reporting and responding to child abuse. Importantly, these guidelines promote an understanding of the relevant contribution of the different professions in cases of child abuse; in particular, the role of public health nurses in carrying out enquiries in cases where there are child protection concerns and where they already have a close relationship with the family involved. These guidelines highlight the need for family-centred child care and protection and the formation of effective partnerships for consistent service provision, as well as serving as a framework for multidisciplinary and inter-agency working practices. Throughout, the welfare of the child is emphasised as of paramount importance. Wider areas addressed within these guidelines include underage pregnancy, peer abuse, bullying, vulnerable children, abuse outside of the hom e, allegations of abuse against employees and volunteers, and organised abuse. The Best Health for Children: Developing a Partnership with Families strategy (DoHC, 1999b) is based on a model that focuses on a holistic approach to child health promotion encompassing emotional and psychological aspects of health in addition to physical health. This strategy also acknowledges the importance of the family in this process, particularly the value of parental observations and concerns about their children. This report outlines a core programme for child health surveillance which documents the role of the public health nurse in making home visits soon after birth and throughout the child’s early development. A follow-up report published in 2005 (DoHC, 2005) has reviewed the original programme and made recommendations for greater observation of child behaviour and development and increased awareness of the determinants of child health, together with the formation of partnerships between parents and healthcare professionals to improve child health outcomes. Role of the public health nurse Public health nurses often carry out home-based parental assessment and ongoing surveillance, particularly working with high-risk families; however, in these situations, it can be difficult to build a trusting, supportive relationship if parents feel threatened, powerless, or concerned about possible action being taken against them. Marcellus proposed a framework of rational ethics to develop trusting relationships with high-risk families, based on four themes: mutual respect, engaged interaction, embodiment and creating environment (Marcellus, 2005). Current legislation, guidelines and strategies emphasise the need for improved child protection and care to ensure the welfare of all children. The public health nurse can play a key role in surveillance of high-risk families and may be among the first to detect child abuse. Competence in procedures for identification, reporting and responding to child abuse are therefore essential. The public health nurse works as part of a multidisciplinary team and should promote effective inter-agency partnerships for optimum service provision for children and their families. References Crisp, B. R. Lister, P. G. 2004, ‘Child protection and public health: nurses’ responsibilities’, Journal of Advanced Nursing, vol. 47, no. 6, pp. 656-63. Government of Ireland 1991, Child Care Act 1991. Retrieved 11th December 2008 from:  http://www.irishstatutebook.ie/1991/en/act/pub/0017/index.html Government of Ireland 2001, Children Act 2001. Retrieved 11th December 2008 from:  http://www.irishstatutebook.ie/2002/en/si/0151.html DoHC 1999a, Children First: National Guidelines for the Protection and Welfare of Children. Retrieved 11th December from:  http://www.dohc.ie/publications/children_first.html DoHC 1999b, Best Health for Children: Developing a Partnership with Families. Retrieved 11th December from:  http://www.hse.ie/eng/Publications/Children_and_Young_People/Best_Health_for_Children_Developing_a_Partnership_with_Families.pdf DoHC 2005, Best Health for Children Revisited. Retrieved 11th December from:  http://www.google.co.uk/search?hl=enq=Best+Health+for+Children+RevisitedbtnG=Searchmeta= Marcellus, L. 2005, ‘The ethics of relation: public health nurses and child protection clients’, Journal of Advanced Nursing, vol. 51, no. 4, pp. 414-20. United Nations 1989, UN Convention on the Rights of the Child: the articles. Retrieved 11th December 2008 from:http://www.unhchr.ch/html/menu3/b/k2crc.htm Maths Teaching Guide: Geometrical Constructions Maths Teaching Guide: Geometrical Constructions 12 Geometrical Constructions You know using various instruments of the geometry box-ruler, compass, protractor, divider, set square etc. construction of lines and angles. construction of perpendicular and perpendicular bisector to a line construction of angle bisectors. Construction of special angles like 15 °,30 °,45 °,60 °,75 °,90 °,105 °,120 °,135 °,150 °,175 ° You will learn construction of parallel lines using different techniques- paper folding, set square and using compass. to identify whether a triangle can be constructed with the given measurements. construction of triangles with given measurement of sides and angles. We know parallel lines are lines that never meet. Now let us learn to construct parallel lines. Construction of parallel lines using ruler and set squares To construct a parallel line to a given line from a given point Steps for construction: 1.Draw a line l and take a point O outside the line.O 2.Place any side of the set square forming the rightl angle along the line l. 3.Place the ruler along the other side of the set square forming a right angle as shown. This ruler is to be kept fixed.O l 4.Slide the set square along the ruler upwards such that point O lies along the arm of the set square. O l 5.Remove the ruler and draw a line along the setOm square. Name this line as ml m is the required line parallel to l ∠´ l à ¯Ã‚ £Ã‚ ¬Ãƒ ¯Ã‚ £Ã‚ ¬m Om l Construction of parallel lines using ruler and compass Steps for construction: 1. Draw a line l and take a point A outside the line. A l 2. Take any point B on the line. Join A to B. A l B 3. With B as the centre and any convenient radius, draw an arc intersecting line l at P and AB at Q. A Q l BP 4. With A as the centre and the same radius draw an arc to intersect AB at R. A Q l BP 5. With the compass measure the distance between points P and Q. 6. With R as the centre and radius equal to PQ, draw an arc intersecting the previous arc at S SA Q l BP 7. Draw a line through A and S. m is the required line parallel to l passing through the point A. l à ¯Ã‚ £Ã‚ ¬Ãƒ ¯Ã‚ £Ã‚ ¬m SAm Q l BP Remember only one line can be drawn through A which is parallel to l. Lab Activity We have already studied parallel lines and their properties. We know that when 2 parallel lines are intersected by a transversal, the alternate angles so formed are equal. The above construction has been done using the same property. When 2 parallel lines are intersected by a transversal, then the corresponding angles so formed are also equal. Using this property, construct a pair of parallel lines. To construct a parallel line to a given line at a given distance To draw a parallel line at a fixed distance from a given line follow the steps given below Draw line l. Construct a perpendicular on the given line. Take a point at the given distance on the perpendicular. Construct a parallel line at that point as in the previous construction. Example 1Draw a line l. Draw another line m parallel to l at a distance of 4 cm from it. Solution To construct a line parallel to a given line at a fixed distance from it we will follow the following steps Take a point C on the line l. Draw a perpendicular at the point C. On the perpendicular mark a point at a distance of 4 cm from C (say G). At G draw a GH perpendicular to CG. Since GH ⊠¥ CG and CG ⊠¥ l ∠´ l à ¯Ã‚ £Ã‚ ¬Ãƒ ¯Ã‚ £Ã‚ ¬ GH GHm F DE l ACB (since the sum of the interior angles on the same side of the transversal CG is 180 °) Thus, m à ¯Ã‚ £Ã‚ ¬Ãƒ ¯Ã‚ £Ã‚ ¬ l at a distance of 4 cm from l. Exercise 12.1 1.Draw a line AB = 6 cm. Mark a point P anywhere outside the line AB. Draw a line CD parallel to line AB passing through the point P a.  by drawing alternate angles b.  by drawing corresponding angles. 2.  Draw a line AB. Draw a line CD perpendicular to line AB. Now on CD mark a point P at a distance of 4.5 cm from C. At the point P draw a line parallel to given line AB. 3.  Refer to the figure given alongside. Construct a line parallel to AB passingD  through the point P. Draw another line parallel to CD also through the  point P. Name the geometrical plane figure so formedP AB C 5.  Draw a line XY= 8 cm. On the line XY mark a point A, 3 cm from X. At the point A draw a perpendicular AB to the line XY. Mark a point M on AB at a distance of 4 cm from A. draw a line CD parallel to XY passing through M. 6.  Draw a line parallel to a given line at a distance of 5.5 cm from it. Construction of triangles A A triangle is a three sided closed figure. It has 6 elements -3 sides and 3 angles. For triangle ABC given alongside, sides are AB, BC, and CA and the angles are ∠ ABC, ∠ BCA and ∠ CBA However to construct a triangle uniquely, we do not need the measure of all six parts. A triangle can be drawn with a definite given size if any BC of the 3 conditions given below are fulfilled. ÂÅ   The three sides of the triangle are given SSS criterion Two sides and the included angle are given SAS criterion. One side and any two angles are given AAS criterion or ASA criterion. Use a compass to draw angles of special measures 15 °, 30 °, 45 °, 60 °, 75 °, 90 °, 105 °, 120 °, 135 ° etc). For others you can use a protractor to construct triangles with given angles. Remember: A triangle cannot be constructed if 3 angles are given since the length of sides can vary. The triangles will be of the same shape; however the length of the sides will be different. Two sides and the non – included angles are given. Before we construct triangles we should make a rough sketch showing all the given measures. Construction of triangles when 3 sides are given. A triangle can be drawn only when the sum of any two sides is greater than the third side. When three sides of a triangle are given, check whether the sum of any two sides is greater than the third side. If yes, only then the construction is possible. Example 1Which of the following can be the sides of a triangle? a.12,24, 11b.10, 5, 7 Solution a.Add the sides by taking two at a time 12 + 24 > 11 24 + 12 > 15 However 11+12 < 24, hence these measures cannot be the sides of a triangle b.Add the sides by taking two at a time 10 + 5 >7 5 + 7 >10 10 + 7 >5 Since the sum of any two sides is greater than the third side hence these measures can be the measures of a triangle. Example 2Construct a triangle ABC such that AB = 6 cm, BC = 5 cm and CA = 9 cm. Solution In triangle ABC, 9 + 6 > 5, 6 + 5 > 9, 9 + 5 > 6 ∠´ triangle ABC can be constructed. Steps of Construction Draw a rough sketch of the triangle ABC. C 9 cm5 cm A6 cmB Draw a line segment AB = 6 cm A6 cmB With A as the centre and radius = AC=9 cm draw an arc A6 cmB With B as centre and radius = BC= 5 cm draw another arc to intersect the previous arc at C A6 cmB Join A to C and B to C. Triangle ABC is the required triangle. C 9 cm 5 cm A6 cmB Example 3Construct a triangle PQR with PQ = 7 cm, QR = 6 cm and ∠ PQR = 60 °. Solution: Steps of Construction Draw a rough sketch of the triangle PQR R 6 cm 60à ¢- ¦ P7 cmQ Draw a line segment PQ of measure 7 cm. P7 cmQ Using a protractor or a compass construct an angle of 60 °Ã‚  at the point P. X 60 ° P7 cmQ With P as the centre and the radius = PR = 6 cm draw an arc to intersect XP at a point R X R 6 cm 60 ° P7 cmQ Join RQ.X Triangle PQR is the required triangle. R 6 cm 60 ° P7 cmQ To construct a triangle when two angles and the included sides are given- ASA construction Example 4Construct a triangle ABC with ∠ B = 60 °, ∠ C = 70 ° and BC = 8 cm. Draw a rough sketch of the triangle ABC A 6 cm 60 °70 ° B8 cmC Draw a line segment BC of length = 8 cm B8 cmC At B draw ∠ PBC = 60 ° using a compass P 60 ° B8 cmC At C draw ∠ QCB = 70 ° using a protractor the point off intersection of PB and QC is the vertex A. Triangle ABC is the required triangle. QP A 6 cm 60 °70 ° B8 cmC To construct a triangle when two angles and the side not included between the angles is given- AAS construction To construct a triangle when the side is not the included side in the given angles, we will first the third angle using the angle sum property and then consider the given side and the two angles that include that side to construct the triangle using ASA construction criterion. Example 5Construct a triangle PQR with ∠ P = 110 °, ∠ Q= 30 ° and QR = 6.5 cm. Solution: The given side QR is not the included side between the given angles ∠ P and ∠  Q. ∠´ let us find the third angle ∠ R, using the angle sum property We know sum of angles of a triangle = 180 °. ∠ P + ∠  Q + ∠ R = 180 ° ⇒ 110 ° + 30 ° +∠ R = 180 ° ⇒ ∠ R = 180 ° 140 ° = 40 ° Now we can use the ASA construction criterion to construct triangle PQR with ∠ Q =30 °, ∠ R = 40 ° and QR = 6.5 cm. The steps of construction will be the same as in the previous construction Rough sketch PAB P 30 ° 40 ° Q6.5 cmR 30 °40 ° Q6.5 cmR To construct a right triangle when the hypotenuse and one side are given.RHS construction This construction is only for right angled triangles when the hypotenuse and one side are given. One angle is 90 ° as it is a right triangle. Example 6Construct a right triangle XYZ right angled at X with hypotenuse YZ = 5 cm and XY = 3 cm Solution: Since it is a right triangle right angled at X ∠´ ∠ X = 90 °, YZ = 5 cm and XY = 3 Steps of construction Draw a rough sketch of the triangle XYZ Z 5 cm X3 cmY Draw a line segment XY = 3 cm. X3 cmY At X draw ∠ AXY = 90 ° using a compass A 90 ° X3 cmY With Y as the centre and radius 5 cm , draw an arc to intersect AX at Z. A Z 90 ° X3 cmY Join YZ Triangle XYZ is the required triangle. A Z 5 cm 90 ° X3 cmY Remember in a right triangle, the hypotenuse is the longest side. Exercise 12.3 1.  Given below are some measurements of sides, which of the following can be the sides of a triangle. a. 6,8,12 b. 5,9,6 c. 11,6,6 d. 80,15,60 e. 8,6,10 f. 6,6,6 2.  Which of the following measures will form a triangle? Why or why not? a.∠ A = 45 °, ∠ B = 80 °, ∠ C = 65 ° b.∠ X = 30 °, XY = 5.6 cm, XZ = 3.8 cm c.AB = 7 cm, BC = 10 cm, CA = 6 cm d.∠ B = 60 °, ∠ A = 80 °, AC = 5 cm 2.  Construct a triangle ABC with each side measuring 6 cm. Measure the three angles of the triangle so formed. 3.  Construct a right triangle PQR right angled at P with PQ = 4 cm and PR = 6 cm. 4.  Construct a triangle XYZ with ∠ X = 60 °, ∠ Y = 45 ° and XY = 7 cm. 5.  Construct a triangle PQR with PQ = 6 cm, PR = 8 cm and ∠ Q = 75 °. 6.  Construct a triangle ABC with AB = 5 cm, BC = 6 cm, ∠ B = 105 ° 7.  Construct a triangle LMN with LM = LN = 5.8 cm, MN = 4. 6. What special name is given to such a triangle? 8.  Construct a right triangle ABC with AB = 5.5 cm, BC =8.5 cm and ∠ A = 90 ° 9.  Construct a triangle PQR with ∠ P = 45 °, ∠ Q = 75 ° and PQ = 5.5 cm Construct a triangle PQR with measures of sides PQ = 4.6 cm, QR = 5.6 cm and PR = 6.5 cm. 1.Draw the angle bisectors of ∠ P and ∠ Q. let these intersect each otherR at the point O. 2. From the point O draw a perpendicular to any side of the triangle. Name the point where it meets the side as M. 3. With O as the centre and radius OM draw a circle.O Does the circle touch all the sides of the triangle? Such a circle is called an inscribed circle and the centre is known as the  incentre.PMQ Can you draw another circle larger than this which can fit into the triangle? No the inscribed circle is the largest circle that will fit inside the triangle. Math Lab Activity Objective: to make students familiar with constructions Materials required: compass, ruler, paper, pencil and colours. Method: Each student will work individually to create a drawing of his/her initials using the parallel, perpendicular, and segment bisector constructions 1.Make a sketch of your initials and identify where each construction will be used. It is necessary to use at least one Ã…   perpendicular line through a point on a line, Ã…   perpendicular line through a point not on a line, Ã…   parallel line through a point not on the line,  other constructions what you have learned can H I J K L M N Ã…   also be used. 2.Construct using a compass and a ruler. 3.Colour the alphabets and make them as creative as you can. Hint: constructions will be easy if you use the straight lined alphabets as Recollections OPQRSTU V W X Y Z A parallel line can be drawn to a given line from a given point A parallel line to a given line can be drawn at a given distance from it. A triangle has 6 elements in all- 3 sides and 3 angles. A triangle is possible only if the sum of any 2 sides is greater than the third side. Construction of triangles is possible given the following criterions when 3 sides are given. SSS when two sides and an included angle are given.SAS when two angles and the included sides are given.ASA construction when two angles and the side not included between the angles is given. AAS construction a right triangle when the hypotenuse and one side are given. RHS construction Formative assessment 1.Fill in the blanks a.The sum of angles of a triangle is . b.A triangle has elements. c.If 2 angles and the side are given, a triangle can be constructed. d.In a triangle PQR, ∠  P = 45 °, PQ = 7.5 cm and PR = 6.3 cm, then triangle PQR can be constructed using criterion. e.To construct a triangle with given sides, the sum of 2 sides should be than the third side. 2.Which of the following can be the sides of a triangle? a.4 cm, 6 cm, 5 cm.b.2 cm, 5 cm, 4 cmc.8 cm, 6 cm, 12 cm d.5 cm, 6 cm, 12 cm 3.Construct a triangle ABC with the following measurements: a.AB = 5 cm, BC = 7 cm, AC = 13 cm.b.∠ A = 45 °, ∠ B= 65 °, AB = 7 cm. 4.Draw a line parallel to a given line at a distance of 7.5 cm from it. 5.How many lines parallel to a given line can be drawn through a point outside the line? Why? Review Exercise 1.Draw a line segment AB = 6.4 cm. On AB take any point P. At P draw perpendicular PQ to AB. On PQ mark a point at 5 cm from P. Draw a line parallel to given line AB. 2.Draw a right triangle PQR right angled at Q with PQ = 7 cm , QR = 6 cm. through P draw a line parallel to QR and through R draw a line parallel to PQ intersecting each other at S. measure PS and RS. What is the name of the figure so obtained? 3.Construct an isosceles triangle ABC with AB = AC= 7.5 cm and ∠ A = 75 °. 4.Construct an equilateral triangle LMN with each side measuring 6 cm. 5.Construct a right triangle XYZ with XY = 6.5 cm, YZ =8.5 cm and ∠ X = 90 °. 6.Construct an obtuse triangle ABC with ∠ B = 135  °, AB = 7 cm, BC = 8 cm. 7.Construct a triangle PQR with ∠ P = 55 °, ∠ Q = 65 ° and PQ = 6.3 cm 8.Construct a triangle ABC with ∠ A = ∠ B =75 °, and AB = 7.4 cm. What is the special name given to such a triangle? 9.Construct a triangle XYZ with XY = 5.4 cm and ∠ X=60 °, ∠ Z = 60 °. Measure the length of YZ and XZ. What is the special name given to such a triangle? 10.Construct a triangle ABC with the ∠ B = 105 °, AB= 6.3 cm and BC = 5.6 cm.

Effective Foreshadowing in Flannery O’Connor’s Greenleaf Essay

Effective Foreshadowing in Flannery O’Connor’s Greenleaf â€Å"Mrs. May’s bedroom window was low and faced on the east and the bull, silvered in the moonlight, stood under it, his head raised as if he listened- like some patient god come down to woo her- for a stir inside her room. The window was dark and the sound of her breathing too light to be carried outside. Clouds crossing the room blackened him and in the dark he began to tear at the hedge. Presently they passed and he appeared again in the same spot, chewing steadily, with a hedge-wreath that he had ripped loose for himself caught in the tips of his horns. When the moon drifted into retirement again, there was nothing to mark his place but the sound of steady chewing. Then abruptly a pink glow filled the window. Bars of light slid across him as the venetian blind was split. He took a step backward and lowered his head as if to show the wreath across his horns.† (311) An analysis of the introductory paragraph of Flannery O’Connor’s â€Å"Greenleaf† reveals how diction and text structure foreshadow Mrs. May’s fate and create a...

Printing and Key Plate

Mystery of ‘K’ in CMYK The K in CMYK stands for â€Å"Key†, but the answer is much more interesting than that. The â€Å"key plate† is said to add the â€Å"detail† to a printed image. This is true in that the black plate in a four color process print pushes the contrast and creates â€Å"detail†. Many people suggest that the theory of using K instead of B because it may be easily confused with â€Å"Blue† is a myth. While it is highly speculative what the reasoning is, there are context clues as to why it may actually be true.Mark Gatter, in the book he published titled â€Å"Getting it right in print†, states the â€Å"key plate† is used align the other plates, but does not mention why it is called â€Å"key†. While the term today may have adopted the meaning for the process of aligning plates, the term â€Å"key† does not originate from this process. The color â€Å"registration† is more closely rel ated to the process of aligning plates. The term â€Å"key† originates from the rotary printing press in 1843 that had screw keys to control the amount of ink printing on a substrate.Offset presses also use this mechanism. Most other countries who speak languages other than English typically used â€Å"CMYK† to mean four color process; even if the individual colors don’t begin with the same letters. However, in French speaking countries, the accronym is â€Å"CMJN† is used meaning â€Å"Cyan, Magenta, Jaune, Noir†. â€Å"Jaune† and â€Å"Noir† translate to â€Å"Yellow† and â€Å"Black† respectively. This shows that in certain countries, the model directly translates to â€Å"black† and not â€Å"key† or any other term referring to alignment, detail, or contrast.While Johannes Gutenburg invented the printing press in Germany around 1454 which revolutionized moveable type, it was Jacob Christoph Le Blon who invented three-color and four-color process printing around 1725. What is interesting is that his original color models were RYB and RYBK. The argument here is that the color blue (represented by â€Å"B†) is used in the same process as black, so the initial may have been changed to avoid confusion.His three-color process would have used the same aligning technique as his four-color process, so if â€Å"key† was meant to mean â€Å"key plate†, it would theoretically have been the blue plate in his three-color model. While it may never be known the exact origin of the use of â€Å"key†, it can be discerned that the myth could perhaps be true and that the origin of the term could have been to simply avoid confusion with the color blue. It appears the context clues may outweigh the notion that K is used to denote â€Å"detail† or â€Å"contrast†. Source: http://gearsidecreative. com/why-is-the-color-black-represented-with-a-k-in-cmyk/

Colorimeter Essay

Record the absorbance values for 4ppm Methyl orange, making sure to zero the machine with the deionised water cuvette after each reading is taken. After I measured out my methyl orange I diluted each with deionised water up to the calibration mark on the volumetric flask. 4. I then poured each solution into separate cuvettes. 5. Recording the absorbance values for each always â€Å"zeroing† in between each reading with a cuvette containing deionised water. 6. Get the absorbance value of the unknown solution. 7. Record results in Tables 8. Prepare a standard curve graph 9. Estimate the concentration of the unknown solution on your graph. Results Part Two Concentration Discussion Using a colorimeter I used different coloured liquids to prove beer lamberts law. I did this experiment three times each time recording my results. I believe I proved beer lamberts law and this can be seen by my results which I have listed. I was also able to find the concentration of an unknown solution by plotting it on my graph using its absorbance number.